https://old.reddit.com/r/GamersNexus/comments/1ilgii6/rtx_5090fe_molten_12vhpwr/
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P=IV : Power = Current x Voltage
The voltage delivered by power supplies is constant, so if the new card pulls more power, that means there's more current.
This affects the cables:
P=IIR : Power = Current squared x Resistance
In this case, current is the current flowing through the cable and resistance is the total resistance of the contacts and the wire. The power is the power dissipated effectively as heat in the wire.
When you increase current, power dissipation increases in a square relationship (much bigger change in output for a small change in input).
Next thing is that copper wires have a positive temperature coefficient: when they warm up, they increase in resistance.
Contacts don't connect to their mating surfaces uniformly; there's usually small 'hotspots' of contact where current passes through. Shitty or worn connectors may not contact well (few hotspots), which can increase the effective resistance, increasing heat dissipation, thus increasing temperature.
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Yeah that's all fine, good, and correct, but it doesn't explain why the initial poster thinks that adding current will add resistance.
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You did an impressive job of practically explaining ohms and watts law in layman's terms fwiw.
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Aww ty
I went back and fixed a few minor things
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He possibly means energy lost due to the resistance of the material increases proportionally to the amount of energy drawn through the wire
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All those words won't bring your pappy back
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The massive voltage drop over my 2cm cable
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