Dramatards doing the maths :marseymath:

!mathematics identify yourselves

45
Jump in the discussion.

No email address required.

!r-slurs if you don't want to look like a true r-slur memorizing hundreds of formulas like {n X (n+1) X (2n+1)} to sum the squares from 1 to 14 and then subtract the sum of squares of 1 to 9 the easy thing is to shortcut with number theory.

Each subsequent square increases the difference by 2, each subsequent cube increases the difference by 6

10^2 = 100, 11^2 = 121, difference 21, 21+2 = 23, so 12^ 2 = 121 +23 = 144

So 10^2 + 11^2 +12^2 + 13^2 + 14^2 = 100X5 + 21X4 + 23X3 + 25X2 + 27 = 730

Jump in the discussion.

No email address required.

For the cubes, each subsequent cube increases the difference by (6 * (n-1)) where n is the bigger number being cubed.

so 1³ is 1, 2³ is 8 (difference of [1 + (6 * (2-1))]), 3³ is 27 (difference increased by 12, from 7 to 19), etc.

Jump in the discussion.

No email address required.

You're looking at this the wrong way. If you go by that logic you have to find a new number for every higher order power.

The general rule of power is

(n+1)^k = n^k + X (where x can be calculated via a difference of differences method)

For (n+1)^k the constant difference is found at the k-th difference of differences

And the constant is = (constant for k-1)×k

Constants:

For squares it's 2, found at the just the ordinary difference of differences

For cubes it's 2*3, found at the diff of diff of diff (3rd order)

4th power constant is 6*4 found at the 4th order d-o-d

5th is 24*5 found at the 5th order d-o-d

And so on

!mathematics someone give the generalized algebraic proof to this. It's basic number theory

Jump in the discussion.

No email address required.

Neighbor I was just correcting your assertion that the diff increased by 6 between cubes

I'm sure you are correct with all this shit though

Jump in the discussion.

No email address required.

Jump in the discussion.

No email address required.

Ok moron. Now try taking the 3rd order difference of 1³, 2³, 3³, 4³, 5³

1st order:

|1 - 8| = 7 ; |8-27| = 19 ; |27-64| = 37 ; |64-125| = 61

🍭 𝟤𝓃𝒹 🌸𝓇𝒹𝑒𝓇 🍭

|7 -19| = 12 ; |19 -37| = 18 ; |37 - 61| = 24

‧͙☆༓。3𝓻𝓭 𝓸𝓻𝓭𝓮𝓻.。༓☆‧͙

|12-18| = ☆‧͙𝟞‧͙☆ ; |18-24| = ☆‧͙𝟞‧͙☆

Hope that wasn't too hard for you champ. Even the most braindead student learns this in fricking crayon when they're 9.

Jump in the discussion.

No email address required.

no way u really made an alt just to sneed at me about nth order differences when higher order diffs were never mentioned in the first place :marseykekw:

surely this is some other devious chad playing an epic prank :marseyoctopus2:

Jump in the discussion.

No email address required.

For (n+1)^k the constant difference is found at the k-th difference of differences

Literally the 4th sentence of his post.

Jump in the discussion.

No email address required.

BIPOC that was the post you made AFTER I had already BUCK checked :marseytariq: your towering skyscraper brain with my :marseynerd3: results-oriented, customer service chad reading comprehension

!r-slurs get your boy he's gone rogue

Jump in the discussion.

No email address required.

There is nothing I can do for the people of this website. You are all human worms.

Jump in the discussion.

No email address required.

That's not me bruh :#marseyfacepalm:

Jump in the discussion.

No email address required.

Link copied to clipboard
Action successful!
Error, please refresh the page and try again.